In the following, c = 0.4?
If f(x) = 1+ e^x cos x
For the given value of c, find f '(c)
In the following, c = 0.4?
gt
f(x) = 1 + e^x cosx
f'(x) = 0 + e^x (-sinx) + cosx e^x
f'(x) = -e^x sinx + cosx e^x
f'(x) = e^x ( -sinx + cosx)
f'(c) = e^c (-sinc + cosc)
f'(c) = e ^ 0.4 ( -sin0.4+ cos 0.4)
f'(c)=e^0.4 ( -0.0069 + 0.9999)
f'(c) = e^0.4 (0.993)
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